- Messages
- 70
- Country

Hi everyone,
I've been working on engine modeling for some time now, and as a basis for my work/ research, I've used Roy's "FS Thrust versus Altitude" paper.
The temperature ratio, represented as theta, is given by the following formula: (288.15-1.98*altitude/1000)/288.15. Quick question: does this take into account non-ISA temperature conditions?
Quick example:
ISA+0 @ 5,000 ft
theta = (288.15-1.98*altitude/1000)/288.15 = 0.965642
theta = Ta/To = (273.15 + 5.1) / 288.15 = 0.965642
ISA+10 @ 5,000 ft
theta = (288.15-1.98*altitude/1000)/288.15 = 0.965642
theta = Ta/To = (273.15 + 5.1 + 10) / 288.15 = 1.000347
I've been working on engine modeling for some time now, and as a basis for my work/ research, I've used Roy's "FS Thrust versus Altitude" paper.
The temperature ratio, represented as theta, is given by the following formula: (288.15-1.98*altitude/1000)/288.15. Quick question: does this take into account non-ISA temperature conditions?
Quick example:
ISA+0 @ 5,000 ft
theta = (288.15-1.98*altitude/1000)/288.15 = 0.965642
theta = Ta/To = (273.15 + 5.1) / 288.15 = 0.965642
ISA+10 @ 5,000 ft
theta = (288.15-1.98*altitude/1000)/288.15 = 0.965642
theta = Ta/To = (273.15 + 5.1 + 10) / 288.15 = 1.000347


