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Is there a simple way to model this graph? My feeling is that every line would have to be individually calculated.
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I'm afraid I don't know that as yet. I only acquired the graph last Sunday. I have put out a query to the "eggsperts". I was told that at SL the max P7 was 74 so as you say the dotted line is a bit confusing.What is the significance of the diagonal dotted line from 68 to 73 Hg?

It says it right on the graph...What is the significance of the diagonal dotted line from 68 to 73 Hg?

It says it right on the graph...
Anti-icing on- within dotted line reduce P7 by:-
Aircraft 0.7" Hg
Engine 0.7" Hg
Both 1.4" Hg
I'm pretty certain this is because engine anti-ice on is going to impact pressure levels.



The chart is represented as distinct arrays of up to 4 sets of data where the X value is the temperature and the Y value is the P7 limit, and the arrays represent the altitude values. You would have to know how many data points were valid in each array since some of the lines have 3 distinct X/Y positions and others have 4.

Thanks Roy,For a standard atmosphere your P7 varies at close to atmospheric pressure ratio.
For example at sea level 15°C P7 is about 73.8, at 4000 feet it is 64.1 at 8000 ft it is 55.3
Atmospheric pressure ratio for 4000 ft is 0.864, times 73.8 gives P7=63.8, at 8000 ft use .74 * 73.8 = 54.6
Atmospheric pressure ratio (delta) is theta^5.256 where:
theta = (288.15-1.98*altitude/1000)/288.15
You could decrease the 5.256 power slightly to more closely match your chart numbers, for example if you made it 5.11 the 4000 and 8000 values are correct to the accuracy of reading the chart
I would expect that non-standard atmosphere results would be somewhat similar to model.
Roy


I was wondering if in effect I would have to maske up to 4 different calculations for each line. If I can get a sort of ball park figure that's no mopre than half a point out that would do.
S.L.
-40, 15, 25, 45
72.4, 73.8, 72.7, 64.0
1000
-40, 5, 25, 43
73.1, 72.7, 70.2, 61.8
ALT=0 TEMP=15
(72.7-73.8)/(25-15)*(15-0)+73.8 = 73.8
ALT=1000 TEMP=15
(70.2-72.7)/(25-5)*(15-5)+72.7 = 71.45
AIRCRAFT ALT = 350
(73.8-71.45)/(1000-0)*(350-0)+71.45 = 72.9775




For Torino, using the equations in post#7 I get 71.25, Warp D gets 71.45, both using ISA. His is closer to the chart
Roy


Thanks RP I'll try that out.288.15 (L:N118, number) 1000 / 1.98 * - 288.15 / 5.11 pow 73.8 *
